34 lines
641 B
Markdown
34 lines
641 B
Markdown
|
|
||
|
|
|
||
|
|
|
||
|
|
<img src='../../../../../assets/logo.png' style='zoom: 80%;' align=left /> <font size='10'>Oddly Even</font>
|
||
|
|
|
||
|
|
1<sup>st</sup> October 2024
|
||
|
|
|
||
|
|
Prepared By: ir0nstone
|
||
|
|
|
||
|
|
Challenge Author(s): ir0nstone
|
||
|
|
|
||
|
|
Difficulty: <font color='green'>Very Easy</font>
|
||
|
|
|
||
|
|
# Synopsis
|
||
|
|
Given a number, print "even" if it is even and "odd" if it is odd.
|
||
|
|
|
||
|
|
## Skills Required
|
||
|
|
* Basic Python
|
||
|
|
|
||
|
|
# Solution
|
||
|
|
First, we take in the number:
|
||
|
|
|
||
|
|
```py
|
||
|
|
a = int(input())
|
||
|
|
```
|
||
|
|
|
||
|
|
We can then check if the number is divisible by `2`. If it is, we print "even", otherwise we print "odd".
|
||
|
|
|
||
|
|
```py
|
||
|
|
if a % 2 == 0:
|
||
|
|
print('even')
|
||
|
|
else:
|
||
|
|
print('odd')
|
||
|
|
```
|