added official hacktheboo2024 writeups

htb/hacktheboo2024/coding/[Very Easy] oddly_even/Dockerfile

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+FROM registry.htbsvc.net/hackthebox/htb:coding_template
+
+COPY --chown=root challenge/challenge.py /root/checker
+COPY --chown=root challenge/flag.txt /root/checker
+COPY --chown=www-data challenge/index.html /app/templates
+
+EXPOSE 1337

htb/hacktheboo2024/coding/[Very Easy] oddly_even/README.md

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+![img](../../../../../assets/htb.png)
+
+
+<img src='../../../../../assets/logo.png' style='zoom: 80%;' align=left /> <font size='10'>Oddly Even</font>
+
+1<sup>st</sup> October 2024
+
+Prepared By: ir0nstone
+
+Challenge Author(s): ir0nstone
+
+Difficulty: <font color='green'>Very Easy</font>
+
+# Synopsis
+Given a number, print "even" if it is even and "odd" if it is odd.
+
+## Skills Required
+* Basic Python
+
+# Solution
+First, we take in the number:
+
+```py
+a = int(input())
+```
+
+We can then check if the number is divisible by `2`. If it is, we print "even", otherwise we print "odd".
+
+```py
+if a % 2 == 0:
+    print('even')
+else:
+    print('odd')
+```

htb/hacktheboo2024/coding/[Very Easy] oddly_even/build_docker.sh

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+#!/bin/bash
+docker build --tag=coding_oddly_even .
+docker run -p 1337:1337 --rm --name=coding_oddly_even -it coding_oddly_even

htb/hacktheboo2024/coding/[Very Easy] oddly_even/challenge/challenge.py

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+import random
+
+def even_or_odd(n):
+    if n % 2 == 0:
+        return 'even'
+    return 'odd'
+
+def gen_question():
+    n = random.randint(1, 100_000)
+
+    return f'{n}', f'{even_or_odd(n)}'

htb/hacktheboo2024/coding/[Very Easy] oddly_even/challenge/flag.txt

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+HTB{15_iT_0dD_oR_Is_iT_n0t?}

htb/hacktheboo2024/coding/[Very Easy] oddly_even/challenge/index.html

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+{% extends "base.html" %}
+
+{% block title %}
+Oddly Even
+{% endblock %}
+
+{% block content %}
+<p>
+    Take in a number, print "odd" if odd and "even" if even.
+</p>
+{% endblock %}
+
+{% block example_input %}
+<p>
+    3
+</p>
+{% endblock %}
+
+{% block example_output %}
+<p>
+    odd
+</p>
+{% endblock %}

htb/hacktheboo2024/coding/[Very Easy] oddly_even/solutions/solve.py

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+a = int(input())
+
+if a % 2 == 0:
+    print('even')
+else:
+    print('odd')